Answer
$N= 8.33 \times 10^{28} atoms/m^{3} $
Work Step by Step
Required:
Number of atoms per cubic meter in Cr
Solution:
$ p= 7.19 g/cm^{3}$
$A_{Cr} = 52.00 g/mol $
Using Equation 4.2:
$N = \frac{N_{Cr}p_{Cr}}{A_{Cr}} =\frac{(6.022 \times 10^{23} atoms/mol)(7.19 g/cm^{3})}{52.00 g/mol} = 8.33 \times 10^{22} atoms/cm^{3} = 8.33 \times 10^{28} atoms/m^{3} $
