Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 3 - The Structure of Crystalline Solids - Questions and Problems - Page 103: 3.70a

Answer

$d_{211} = 0.1347 nm$

Work Step by Step

Required: The metal niobium (Nb) has a BCC crystal structure. If the angle of diffraction for the (211) set of planes occurs at 75.99° (first-order reflection) when monochromatic x-radiation having a wavelength of 0.1659 nm is used, compute the interplanar spacing for this set of planes Solution: Using Equation 3.21 and considering that 2θ = 75.99°, $d_{211} = \frac{nλ}{2sinθ} = \frac{(1)(0.1659 nm)}{(2) (sin \frac{75.99°}{2})} = 0.1347 nm$
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