Answer
$μ = 1.26 \times 10^{-6} H/m$
Work Step by Step
Given:
magnetic flux density (B)= 0.630 tesla
$H _{field }= 5 \times 10^{5} A/m $
Required:
magnetic permeability (μ)
Solution:
Using Equation 20.2:
$μ = \frac{B}{H} = \frac{0.630 tesla}{5 \times 10^{5} A/m} = 1.26 \times 10^{-6} H/m$
