Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 2 - Atomic Structure and Interatomic Bonding - Questions and Problems - Page 48: 2.5b

Answer

$2.73\times10^{26}atoms/lb.mol$

Work Step by Step

We have 453.6 g/lbm so $1lb.mol=(453.6 g/lbm)(6.022\times10^{23} atoms/g.mol)=2.73\times10^{26}atoms/lb.mol$
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