Answer
σ = 0.028 $(Ω*m)^{-1}$
Work Step by Step
Given:
electron concentration = 5 x $10^{17}$ $m^{-3}$
electron drift velocity = 350 $\frac{m}{s}$
electric field = 1000 $\frac{V}{m}$
Required:
conductivity (σ)
Solution:
To compute the conductivity of the material, Equation 18.16 will be used.
σ = n|e|$µ_{e}$
Compute first the value of electron mobility using Equation 18.7:
$µ_{e}$ = $\frac{V^{d}}{E}$ = $\frac{350 \frac{m}{s}}{1000 \frac{V}{m}}$
$µ_{e}$ = 0.35 $\frac{m^{2}}{V-s}$
Substituting the computed value in Equation 18.16;
σ = $(5 \times 10^{17} m^{-3})(1.602 \times 10^{-19} C)(0.35 \frac{m^{2}}{V-s})$
σ = 0.028 $(Ω*m)^{-1}$
