Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 18 - Electrical Properties - Questions and Problems - Page 779: 18.10b

Answer

t= 3.4 $\times 10^{-4}$ s

Work Step by Step

Given: l = 25 mm $v_{d}$ = 72.5 $\frac{m}{s}$ Required: The time, t, required to traverse the given length Solution: t= $\frac{l}{v_{d}}$ = $\frac{25 \times 10^{-3}m}{72.5 \frac{m}{s}}$ = 3.4 $\times 10^{-4}$ s
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