Answer
$v_{d}$ = 72.5 $\frac{m}{s}$
Work Step by Step
Given:
Room temperature of Si = 0.145 $\frac{m^{2}}{V-s}$ (from Table 18.3)
Magnitude of electric field = 500 $\frac{V}{m}$
Required:
drift velocity
Solution:
Using the equation:
$v_{d}$ = $µ_{e}$E = (0.145 $\frac{m^{2}}{V-s}$)(500 $\frac{V}{m}$) = 72.5 $\frac{m}{s}$
