Answer
$J = 3.04 \times 10^{5} A/m^{2}$
Work Step by Step
Required:
current density
Solution:
From Item 18.5b, $I= 5.97 A$
Thus:
$J = \frac{I}{A} = \frac{I}{π(\frac{d}{2})^{2}} = \frac{5.97 A}{π(\frac{5 \times 10^{-3} m)}{2})^{2}} = 3.04 \times 10^{5} A/m^{2}$
