Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 17 - Corrosion and Degradation of Materials - Questions and Problems - Page 722: 17.14

Answer

CPR = 36.48 mpy

Work Step by Step

Given: corrosion current density = 8 $\times$ $10^{-5}$ = 80 $\frac{µA}{cm^{2}}$ Form Prob. 17.13, K = 0.129 Required: CPR in mpy Solution: CPR = $\frac{KAi}{np}$ = $\frac{(0.129)(55.85\frac{g}{mol})(80\frac{µA/}{cm^{2}})}{(2)(7.9\frac{g}{cm^{3}})}$ CPR = 36.48 mpy
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