Answer
CPR = 36.48 mpy
Work Step by Step
Given:
corrosion current density = 8 $\times$ $10^{-5}$ = 80 $\frac{µA}{cm^{2}}$
Form Prob. 17.13, K = 0.129
Required:
CPR in mpy
Solution:
CPR = $\frac{KAi}{np}$ = $\frac{(0.129)(55.85\frac{g}{mol})(80\frac{µA/}{cm^{2}})}{(2)(7.9\frac{g}{cm^{3}})}$
CPR = 36.48 mpy