Answer
CPR in mm/yr = 0.95 mm/yr $\approx$ 1.0 mm/yr
CPR in mpy = 37.42 mpy $\approx$ 37.4 mpy
Work Step by Step
Given:
A = 100 $in^{2}$
W = 485 g
p = 7.9 $\frac{g}{cm^{3}}$
Required: CPR in mm/yr and mpy
Using Equation 17.23,
CPR (mm/yr) = $\frac{KW}{pAt}$
CPR = $\frac{(87.6)(485g)(10^{3} \frac{mg}{g})}{(7.9\frac{g}{cm^{3}})(100 in^{2})(\frac{2.54 cm}{1 in})^2(24 \frac{hr}{day})(\frac{365 day}{yr})(1 yr)}$
CPR in mm/yr = 0.95 mm/yr $\approx$ 1.0 mm/yr
CPR (mpy) = $\frac{KW}{pAt}$
CPR = $\frac{(534)(485g)(10^{3} \frac{mg}{g})}{(7.9\frac{g}{cm^{3}})(100 in^{2})(24 \frac{hr}{day})(\frac{365 day}{yr})(1 yr)}$
CPR in mpy = 37.42 mpy $\approx$ 37.4 mpy
