Answer
$σ_{fs} = 43.82 MPa$
Work Step by Step
Given:
Refer to the given Table.
From Item 12.52a, $σ_{0} = 59.86 MPa$, n = 1.56
Required:
Flexural strength for a 0.20 volume fraction porosity.
Solution:
Rearranging Equation 12.10:
$σ_{fs} = σ_{0} e^{(-nP)} = (59.86 MPa) e^{[-(1.56)(.20)] }= 43.82 MPa$
