Answer
$σ_{0} = 126.66 MPa $
Work Step by Step
Required:
Using the data in Table 12.5, determine the flexural strength for nonporous MgO, assuming a value of 3.75 for n in Equation 12.10.
Solution:
From Table 12.5, $P =0.05, \ σ_{fs} = 105 MPa$, and, for nonporous material, $P = 0$ and $ln σ_{0} = ln σ_{fs}$
Using Equation 12.10 to compute the value of $n$:
$ln σ_{fs} = ln σ_{0} - nP = ln (105 MPa) + (3.75)(0.05) = 4.8415$
$σ_{0} = e^{4.8415} = 126.66 MPa $
