Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 12 - Structures and Properties of Ceramics - Questions and Problems - Page 506: 12.17b

Answer

a = 0.434 nm

Work Step by Step

a = $2r_{fe2+}$ + $2r_{O2-}$ a = 2(0.077nm) + 2(0.140nm) a = .434 nm
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