Answer
(a) is not dimensionless
(b) is dimensionless
(c) is not dimensionless
(d) is not dimensionless
Work Step by Step
(a) $ V \times L \times \nu = L T^{-1} \times L \times L^{2} T^{-1} $ = $ L^{4} T^{-2} $
(b) $\frac{V L}{\nu } = \frac{L T^{-1} L}{L^{2} T^{-1}} $ = $L^{0} T^{0}$ where any unit of zero is equal to 1
(c) $ V^{2} \times \nu = L^{2} T^{-2} \times L^{2} T^{-1}$ =$ L^{4} T^{-3}$
(d) $ \frac{V}{L\nu} =\frac{L T^{-1}}{L L^{2}T^{-1}}= L^{-2} $
