Mechanics of Materials, 7th Edition

Published by McGraw-Hill Education
ISBN 10: 0073398233
ISBN 13: 978-0-07339-823-5

Chapter 1 - Problems: 1.22

Answer

$$a = 10.82 \space in$$

Work Step by Step

1)Maximum applied load (Limited by compressive strength of steel) $\sigma_{st} = \frac{P_{max}}{11.7\space in^2} = 30\space ksi$ Solving for $P_{max}$ : $P_{max} = 351\space kip$ 2)Bearing Plate dimensions (limited by compressive strength of concrete): $\sigma_{conc} = \frac{P_{max}}{A_{PLATE}} = \frac{351\space kip}{a^2} = 3.0 \space ksi$ Solving for unknown quantity, a: $a = \sqrt{\frac{351\space kip}{3.0\space ksi}} = \boxed{10.82\space in}\space\space\leftarrow ANS$
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