Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 1 - General Principles - Problems - Page 15: 19

Answer

$1.04kip$

Work Step by Step

We are given that a concrete column has a diameter of 350 mm and a length of 2 m and has a density of $2.45 Mg/m^3$. We are asked to determine the weight of the column in pounds. First we find the volume of the cylinder. $V=\pi r^2 h=\pi (.350m /2)^2 *2m= 0.1924 m^3$ Now we can find the weight: $0.1924 m^3 *\frac{2.45Mg}{1m^3} * \frac{10^3kg}{1Mg}*\frac{2.20lb}{1kg}*\frac{1kip}{1000lb}=1.04kip$
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