## Electrical Engineering: Principles & Applications (6th Edition)

$i_c=1A$ $i_e=5A$ $i_f=-3A$ $i_g=-7A$
Given $i_a = 2 A, i_b = 3 A, i_d = −5 A$, and $ih = 4 A$. Apply KCL at each node to find: $i_c=i_b-i_a=1A$ $i_e=i_c+i_h=5A$ $i_f=i_a+i_d=-3A$ $i_g=i_f-i_h=-7A$