Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.3 - Problems - Power and Enery: P1.27

Answer

42 hours 1.26kWhr 30 cents per kWhr

Work Step by Step

$12.6V\times100Ahr\div30W=42hr$ $12.6V\times100Ahr\div1000Whr/kWhr=1.26kWhr$ $\$95\div(250\times1.26kWhr)=\$0.301\ per\ kwhr$
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