## Electrical Engineering: Principles & Applications (6th Edition)

Charge during interval: $$360,000C$$ and energy delivered: $$3.6\times10^{6} J$$
Current times time equals charge. $10A\times10hr\times\frac{60min}{hr}\times\frac{60s}{min}$ Power is voltage times current, which then can be multiplied by time to find energy. $10V\times10A\times36000s$