Answer
a) 100 dollars, 200 units demanded and supplied
b) The quantity sold is $200-\frac{2}{3}*T$, and the price is $100-\frac{1}{3}*T$.
c) $R = T*200-\frac{2}{3}*T$; Please see the first graph for the relationship.
d) The deadweight loss is $\frac{T^2}{3}$.
e) A tax of 200 dollars is bad since there are better tax levels that would collect more tax and have a lower deadweight loss. At a tax of 150 dollars, tax revenue increases to 15,000 dollars, and the deadweight loss decreases to 7,500 dollars.
Work Step by Step
a)
$Q^{S}=2*P$
$Q^{D}=300-P$
$2*P=300-P$
$2P=300-P$
$2P+P=300-P+P$
$3P=300$
$3P/3=300/3$
$P=100$
$2*P$
$2*100$
$200 = Q^{S} = Q^{P}$
b)
$Q^{S}=2*P$
$Q^{D}=300-(P+T)$
$2P=300-P-T$
$2P+P=300-P-T+P$
$3P = 300-T$
$3P/3 = (300-T)/3$
$P = 100-\frac{1}{3}*T$ (price received by sellers)
Buyers pay the amount sellers receive and the amount of the tax
$P+T = 100-\frac{1}{3}*T+T$
$P+T = 100+\frac{2}{3}*T$
$Q^{S}=2*P$
$Q^{S}=2*P = 2*(100-\frac{1}{3}*T)$
$Q^{S}=200-\frac{2}{3}*T$
c)
$Q^{S}=200-\frac{2}{3}*T$
revenue is the tax * quantity
$Q^{S}=200-\frac{2}{3}*T$
$R = T*200-\frac{2}{3}*T$
d) The orange line on the first graph is the height of the triangle, $\frac{2T}{3}$. The green line on the first graph is the base of the triangle, $T$.
$2/3*T*T*1/2$
$T^2*2/3*1/2$
$1/3*T^2$
The second graph shows the deadweight loss relationship for $T$ between $0$ and $300$.
e)
tax revenue = tax per item * quantity sold
$R = 200 * 200-(2/3)(200)$
$R=200*200-(400/3)$
$R=200*(600/3-400/3)$
$R=200*200/3$
$R=40000/3$
$R=13,333.33$
deadweight loss = $T^2/3$
$DWL = T^2/3$
$DWL = 200^2/3$
$DWL = 40000/3$
$DWL = 13,333.33$
If we reduced the tax to 150 dollars, the tax revenue would be as follows:
$150*(200-2/3*T)$
$150*(200-2/3*150)$
$150*(200-100)$
$150*100$
$15000$
Deadweight loss = $T^2/3$
$DWL = 150*150/3$
$DWL = 22500/3$
$DWL =7500$